Matematika Sekolah Menengah Pertama Carilah himpunan akar persamaan dengan cara penyelesaian akar kuadrat di bawah ini "Pemfaktoran":
1. x² +7x - 30=0
2. 2 x2 - 5x +3=0
3. 5x2 + 3x - 14-0
4. x²-3x - 10 = 0 69
5. - x2 + 5x −6=0 60
6. x28x+15= 0
7. 5-3x - 2x² = 0​

Carilah himpunan akar persamaan dengan cara penyelesaian akar kuadrat di bawah ini "Pemfaktoran":
1. x² +7x - 30=0
2. 2 x2 - 5x +3=0
3. 5x2 + 3x - 14-0
4. x²-3x - 10 = 0 69
5. - x2 + 5x −6=0 60
6. x28x+15= 0
7. 5-3x - 2x² = 0​

Jawaban:

1. [tex](x + 10)(x - 3) = 0 \\ x = - 10 \\ x = 3[/tex]

2.

[tex] {x}^{2} - 5x + 6 = 0 \\ (x - 6)(x + 1) = 0 \\ x = \frac{6}{2} = 3 \\ x = \frac{ - 1}{2} = - \frac{1}{2} [/tex]

3.

[tex] {x}^{2} + 3x - 70 = 0 \\ (x + 10)(x - 7) = 0 \\ x = \frac{ - 10}{5} = - 2 \\ x = \frac{ 7}{5} [/tex]

4.

[tex](x - 5)(x + 2) = 0 \\ x = 5 \\ x = - 2[/tex]

5.

[tex] {x}^{2} - 5 + 6 = 0 \\ (x - 3)(x - 2) = 0 \\ x = 3 \\ x = 2[/tex]

6.

[tex](x + 5)(x + 3) = 0 \\ x = - 5 \\ x = - 3[/tex]

7.

[tex]2 {x}^{2} + 3x - 5 = 0 \\ {x}^{2} + 3x - 10 = 0 \\ (x + 5)(x - 2) = 0 \\ x = \frac{ - 5}{2} = - 2 \frac{1}{2} \\ x = \frac{2}{2} = 1[/tex]

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